Question

Constants A canoe has a velocity of 0.380 m/s southeast relative to the earth. The canoe is on a river that is fiowing at 0.780 m/s east relative to the earth. (Figure 1) Part A Find the magnitude of the velocity t,y of the canoe relative to the river Express your answer in meters per second. Figure ng 1 of 1 View Available Hint(s) w m/s Previeus Answers Submit 45 x Incorrect; Try Again; 4 attempts remaining

Answer 1

Sol: According to the question, A canoe has a velocity reelative to earth is, vele = 0.380 m/ towards south east direction. - River is flowing with a velocity is, relative to earth Deje = 0.780 m/s towards east direction. Let the relative velocity of canoe relative to reiver is relp. Z _ 1 De 3150 eple So, from the above figure we can say that, The angle between Borse and Base is 45°, so we can write the magnitude of Belgis. ver=truepel = √ (Weselu + (ver) Wheree (Ver) and (werly are the x and y components of Depr. Again, (Ver) = (vrse) x + (resede and, (verly = (volely + (vejely Now from figure, (veled= Vele Cos 3150 z vele Cos (90 x 3 + 45 ) [Angle taken Veje = vele Sim 45° z Vele Cos 450 za 0.380 V2 -= 0.268 m/s in anticlock wise dircect -im ]

(vejedy= dele Sim 315o = veje Sim (90x3 +45°) = - Vele Cos 45o = - Were Sim 45° 0.380 o = -0.268 ms and (Bejel u Vele cos oo Voje = 0.780 m/s (vergely=&pje Sim 0 = 0 m/s So, we can write, (Ver) = (Upjela (resede = 0.780 + 0.268 = 1.048 ms (ver)y= (Vr/e)y + (vele)y = 0 - 0.268 = – 0.268 ms. = هے یه رود (23) + مر م) = √(1.048)2 + (- 0.26872 = 1.098 +0.07% = √ 1.169 i 1.081 m/s Thus, the magnitude of the velocity relative to the river is 1.081 ms. Belor of the canoe