Question

The beam of building structure (Fig. 3a) is made of mild steel I-section beam with 80mm deep and 60mm wide as shown in Fig. 36. The beam is bolted (simply supported) onto the girder on both side over a span of 1.0 m. The loading from deck is expected to transfer onto the beam as the form of uniform distributed load, w. The material is to be treated as elastic-perfectly plastic, with yield strength of 240 MPa, and elasticity modulus of 200 GPa. Girder 60 to ott } BO 10 Beam (6) Fig. 3: (a) The building structure and (b) cross-sectional dimension of I-section beam a) Find out the shape factor of the beam b) Find out the magnitude of uniform distributed load, w the beam could sustain for it to have at least 60mm of elastic core depth.

Answer 1

The solution of the given problem is shown in below:-

k B=60 T K bla 1/2 → h=6omm H=80mm IN lo twelomm k tf = 10mm Af=lomm . é Section modulus, z = BH? 6h3 6 GH Toot 2 sox (80) 50 x *(6033 mm² 6 X 80 =(64000 – 22500) mm3 Z = 41500 mm3 CS scanned with CamScanner

Plastic modulus, zp = 3 [B4?_(B-tw) (H = 2# & [sox (80)? (60 -10) (80-2012 3 mm 0 Shape factor = 51000mm3 Plastic modulus of a beam Section modulus of a beam o 51000 fy = Zp = 1:23. Gans) 근 41500 Agping Yield strength, Byt = UDL A Area of beam 3 - 240 = 2 Bhi Hb W (2x 60 x 60 +80x50 W=2688 KN Magnitude of uniformdistributed Load, W = KN x 80 mm Go mm 2688 x 80 KN 60 Don = 3584 kN Cons) - CS Scanned with CamScanner