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Please show clear steps of how to solve each! (1 point) The graph shows the displacement...
(1 point) The graph shows the displacement from equilibrium of a mass-spring system as a function of time after the vertically hanging system was set in motion at time t0. Assume that the units of time are seconds, and the units of displacement are centimeters. The first t-intercept is (0.75, 0) and the first minimum has coordinates (1.25,-1) (a) What is the period T of the periodic motion? seconds (b) What is the frequency f in Hertz? What is the...
(1 point) The graph shows the displacement from equilibrium of a mass-spring system as a function of time after the vertically hanging system was set in motion at time t= 0. Assume that the units of time are seconds, and the units of displacement are centimeters. The first t-intercept is (0.75, 0) and the first maximum has coordinates (1.25, 4). (a) What is the period T = of the periodic motion? seconds (b) What is the frequency f in Hertz?...
(1 point) A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time 0, the resulting mass- spring system is disturbed from its rest state by the force F(t) 70 cos(8t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds. a. Determine the spring constant k Newtons/meter b. Formulate the initial value problem for y(), where y(t) is the displacement...
show all steps please
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 +sin0 0 dt2 where g 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0)~0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum with length...
Differential Equation class. Show the steps for the solutions
please.
Section 3.2 Exercises To Solutions 1. Suppose that the mass is set in motion by moving it upward by 2.5 cm and releasing it with no initial velocity (a) Sketch what you think the graph of y versus t will look like, taking care with the fact that positive y is upward. Make the amplitude of the motion clear on your graph. (b) Express the initial conditions mathematically by giving...
the speed of sound in gelatin and fatty
5. The speed of sound in gelatin and fatty tissue is 1530 m/s. The graph shows the amplitude (in micro meters) of an ultrasonic wave traveling through the tissue versus time (in mi Part 1: What is the wavelength of this wave? Part 2: What is the angular velocity of the wave? y (106 meters) A) 3.1 mm and 126 u radians/second B) 3.1 mm and 3.14 M radians/second C) 3.1 mm...
In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 7.00 cos (4t + ) where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. 6.30 cm (b) At t = 0, find velocity of the piston. -9.11 How do you find the velocity v(t) of an object if you know the position as a function of time,...
(10 pts) A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force F(t) = 170 cos(10t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds. a. Determine the spring constant k. k = 1000 Newtons / meter b. Formulate the initial value problem...
Equations of Simple Harmonic Motion (basic)
PLEASE! show work and only answer if you know how to do it.
People keeps giving me the wrong answer.
Analyzing Newton's 2^nd Law for a mass spring system, we found a_x = -k/m X. Comparing this to the x-component of uniform circular motion, we found as a possible solution for the above equation: x = Acos(omega t) v_x = - omega Asin(omega t) a_x = - omega^2 Acos(omega t) with omega = square...
(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be shown that as a function of time, θ satisfies the differential equation d20 + sin θ-0, 9.8 m/s2 is the acceleration due to gravity For θ near zero we can use the linear approximation sine where g to get a linear di erential equa on d20 9 0 dt2 L Use the linear differential equation...