Question

Hi, I need help writing a code for this. The language is python 3, and we cannot use things like break, continue, exit(), lambda, map, filter, raise, try, except, and assert in our code. Thank you!

We must write a function called "binary_to_decimal(binary_number)" that takes a string for a binary number and output the decimal integer for that number.

The solution, aka the code, MUST contain a for loop of this form (power is an integer variable you define earlier):

which is "for i in range(power, -1, -1):"

We CANNOT use any other loops in our function.

Now the following main block:

if __name__ == '__main__':

   print(binary_to_decimal('11001111'))

   print(binary_to_decimal('00000011'))

   print(binary_to_decimal('100000000011'))

   print(binary_to_decimal('1'))

Will print:

207

3

2051

1

Answer 1

Program :

import math
def binary_to_decimal(binary):
decimal = 0;
power = len(binary)-1
binary = binary[::-1]
for i in range(power, -1, -1):
rem = (int(binary)%10)
decimal = decimal+rem*math.pow(2,power)
power = power-1
binary = int(binary)/10
return int(decimal)

if __name__ == '__main__':
print(binary_to_decimal('11001111'))
print(binary_to_decimal('00000011'))
print(binary_to_decimal('100000000011'))
print(binary_to_decimal('1'))
  

Screenshot of the program :

1 import math 2- def binary_to_decimal(binary): 3 decimal = 0; 4. power = len(binary)-1 5 binary = binary[::-1] 6 for i in range (power, -1, -1): 7 rem = (int(binary)%10) 8 decimal = decimal+rem*math.pow(2, power) 9 power = power-1 10 binary = int(binary)/10 return int(decimal) 12- if name main 13 print(binary_to_decimal('11001111')) 14 print(binary_to_decimal('00000011')) 15 print(binary_to_decimal('100000000011')) 16 print(binary_to_decimal('1')) 11 9 207 3 2051 1 .Program finished with exit code 0 Press ENTER to exit console. I

NOTE: If you want to change something , please let me know through comments; I will surely revert back to you.

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