Question

I have to provide an explantion as to why the output is what it is. why is it when i compile this bit of code i get a count going from 0 to 25. also why does it not display any letters if im using char.

for (int n-0; n<26;n++){

cout <<<char (n+97)-'a'<<endl;

}

Answer 1

The code must be as:

for (int n=0; n<26;n++){

cout <<char (n+97)-'a'<<endl;

}

Otherwise, it is giving compilation errors.

97 is ascii code of 'a'

n goes from 0 to 25

n+97 will goes from 97 to 122 . Thus ascii value of a to z

char(0+97) => 'a'

char(0+97)-'a' = 0

Thus loop will print 0 to 25.

It will print char if whole expression is typecased to character.not the given code.