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Please show all steps and applicable diagrams

W1 W2 M BE 5 •d

a = 2.0m

b = 4.0m

c = 2.0m

d = 6.0m

e = 3.0m

M = 48kN*m

w1 = 8kN/m

w2 = 6kN/m

ye Beam DBE has the cross-section shown in the figure to the right Calculate: c) the vertical position y, of the centroid of

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free bedy diagsom & kN/m & kN/m 6.1) | V₂ 48 KN-m Hp Tys um و سه Зm FBD HAD FBD > DBE FBDEC from ABD of EC O E Horisontal forWe nositive sign for Conna.. Zv=o No= V,+V₂ + 8x6 Vo-Vi = 10+ 48 € 58IWA ** (moment), - V2*6 + 8*6* 6 -Vo*u=0 3 = 51 KN B TheGiven Cross-section - 25 k 150 Ô Yo PS 400 all dimension in mm) Controid 400x25x25 150*25* Ye 400 x 25+ iso *25*2 * (150 +25)Wie we positive syn for compression and Negative sign for Tension stress. as positive moment is saying moment and it will poo

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