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3. Sample Size for Motor Vehicle Ownership: You have been hired by the Ford Motor Company to do market research, and you must
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a) From standard normal tables, we have:
P( -1.96 < Z < 1.96) = 0.95

Therefore the margin of error here is computed as:

MOE= 2* p(1 - p) n

For a prior proportion value of p = 0.86, we have here:

0.03 = 1.96*\sqrt{\frac{0.86(1-0.86)}{n}}

n = 1.96^2*\frac{0.86(1-0.86)}{0.03^2} = 513.92

Therefore 514 is the required sample size here.

b) As we dont have a prior proportion value here, we use p = 0.5 to get a conservative value of sample size here as:

n = 1.96^2*\frac{0.5(1-0.5)}{0.03^2} = 1067.11

Therefore 1068 is the required sample size here.

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