Question

MATLAB

Any guidance is appreciated!

Use meshgrid() function to create 2D grid coordinates with x- and y- coordinates both from -12 to +12 in the increment 1/32. B) Calculate the function z shown below at every (x, y) point and store the result in a 2D array z Z = sin(squareroot x^2 + y^2)/ squareroot x^2 + y^2 c) Find the maximum value in array z and its corresponding index. The array may have more than one maximum points with the same maximum value, you only need to find one of them. Display your results as: The maximum occurs when x is (result) and y is (result). d) Plot the result using the plotting function mesh(x, y, z) (it looks really cool!).

Answer 1

%x-coordinate x=-12:0.03 : 12; %y-coordinate increment by 1/32 ys-12:0.03:12; susing meshgrid %result is stored in [X,Y]=meshgrid (x,y); a 2D array %b, given equation Z= [sin(sgrt (X."2+Y.^2 ) ) / ( sqrt ( X. ^2+Y.^2 ) ) ] ; [max,index]-max (Z); %d, using mesh to plot the results mesh (X,Y,Z);

code:

%a.
%x-coordinate
x=-12:0.03:12;
%y-coordinate
%increment by 1/32
y=-12:0.03:12;

%using meshgrid
%result is stored in a 2D array
[X,Y]=meshgrid(x,y);

%b. given equation
Z=[sin(sqrt(X.^2+Y.^2))/(sqrt(X.^2+Y.^2))];

%c
[max,index]=max(Z);

%d. using mesh to plot the results
mesh(X,Y,Z);