Question

Matlab!

Use Matlab to calculate array X and array Y. The first column is time (1, 2, 3 ...), and the second column is value (0 and 1).
When the value of array X is 0, the value of array Y is itself at the same time.
When the value of array X is 1, the value of array Y will become the value of the previous Y(i-1)

The data of the array is given, just how to change the value of Y at the corresponding time according to the value of X

Save the new results in a new array

2 92133x2 double 1 ou A WN 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17

Answer 1

%   Sample data for testing
Data = [[1:50]' randi([0 1],50,1)];

%   Getting X and Y calculated
X = Data(:, 2);
Y = Data(:, 1);

%   Setting Y for X = 0
idx_0 = find(X==0);
Y(idx_0) = Y(idx_0)
%   Setting Y for X = 1
idx_1 = find(X==1);
Y(idx_1) = Y(idx_1-1)

LIVE EDITOR INSERT VIEW % en MY Code Task Control - 4x Refactor - CODE Run Step Aa Normal -> Go To 4 BIUM Find - Text EE NAVIGATE EulersldentityExample.mlx Stop Section E Break SECTION TEXT RUN % Sample data for testing Data = [[1:50]' randi([0 1],50,1)]; % Getting X and Y calculated X = Data(:, 2); Y = Data(:, 1); % Setting Y for x = 0 idx_0 = find (X==0); Y(idx_0) = Y(idx_0) Y = 50x1 M in 000 % Setting Y for X = 1 idx_1 = find(x==1); Y(idx_1) = Y(idx_1-1) Y = 50x1

LIVE EDITOR INSERT VIEW Task Go To Find Aa Normal - Text BIUM - Run Step Stop Control - A Refactor - CODE Section E Break SECTION RUN NAVIGATE TEXT Eulersidentity Example.mlx idx_0 = find (X==0); Y(idx_0) = Y(idx_0) 10 Y = 50x1 m in 000 % Setting Y for X = 1 idx_1 = find(X==1); Y(idx_1) = Y(idx_1-1) Y = 50x1

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