4. In the electrolysis of acidified water, the anodic reaction is: H2O(l) + 1/202(g) + 2H+(aq)...

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4. In the electrolysis of acidified water, the anodic reaction is: H2O(l) + 1/202(g) + 2H+(aq) + 2e- a. 1.0 Faraday will libe

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Answer 1

Answer #1

2 faraday of electricity will liberate 0.5 moles of oxygen.

1 faraday of electricity will liberate 0.5 /2 = 0.25 moles of oxygen.

0.25 moles of oxygen = 0.25 * 32 = 8g of O2

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4. In the electrolysis of acidified water, the anodic reaction is: H2O(l) + 1/202(g) + 2H+(aq)...

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4. In the electrolysis of acidified water, the anodic reaction is: H2O(l) + 1/202(g) + 2H+(aq)...

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Add Answer to: 4. In the electrolysis of acidified water, the anodic reaction is: H2O(l) + 1/202(g) + 2H+(aq)...

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