Question

Create a function to transpose Array elements as follows: (Problem Set 11 #1)

Transposed 10 X 10 Array -- Sample Output NOTE: This NOT a matrix "transpose". (ie: rows to columns) This is simply moving elements of the array to the opposite order. Ex: (a[1][1] is moved to a[10][10] and a[1][2] is moved to a[9][10] etc. and finally a[10][10] is moved to a[1][1]) ORIGINAL TRANSPOSED 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 1 | 1|7|4|0 9 |4| 8 | 8 | 2 | 4 | 1 | 19 | 2 | 8 | 8|7369| 255 17|1|15|27| 6 | 2 | 81 | 66 | 64 | 43 | 9 | 3 | 1| 4|2|3|2|2|1| 6 | 8 | 5 | 3 | 83 | 1 | 60 | 91 | 5 | 6 | 4 |76|1|89|2|7|95|4| 4 | 84 | 2016 | 8|2||56| ---+---+---+---+---+---+ 5 | 3|1|2|3|3|4|1|1|3 8 | |89|1|39|77|2|4|7| - + - - - + - - - + - - - + - - - + - - - + 6 | 7|4|2|7|7 9 |3|1| 9 | 8 | 6 | 8 3 |1|1| 4|3 3 |2|1|3| -+---+---+---+ 1 | 65 | | 28 | 6 | 24 | 8 7 | 45| 9|7|2|9 8 ||6 7 | 8 | 6 5 | 9 | 10 | 6|1|3| 8 | 8 | 58 | 6 | 1 | 2 | 23 | 24 | 1 | 9 |9|3|4|4| 6 0 | 6 | 6 1 | 8 | 9 | 67|2|5|1|1|7|1|5 5 | 10 | 4 | 9 | 6 3 | 7 | 8 | 8 | 2 | 9|1| 10 | 4 2 | 8 | 8 | 4|90 |4|7|1| +---+---+---+---+---+---+---+---+---+---+ = = = = = = = = = = = = = = =

Answer 1

MATLAB CODE

function A = TransposeArray(A) [row,col]=size(A); % dimension of matrix k=row;  for i=1:row/2 % Will run loop for half number of columns     temp=flip(A(k,:));   % k will contain index of last column and flip  will reverse that column          A(k,:)= flip(A(i,:));   % Swapping rows(flipped) to first and last     A(i,:)=temp;     k=k-1;  % Decrease index of last to last -1 for next swapping                end end

RESULTS :

>> a=[1 2 5 4 3 5;4 4 2 5 5 6;7 52 4 12 8 9]
a =
1 2 5 4 3 5
4 4 2 5 5 6
7 52 4 12 8 9
>> TransposeArray(a)
ans =
9 8 12 4 52 7
4 4 2 5 5 6
5 3 4 5 2 1
>>
>> B=[1 21 15 41 322 52 21;4 4 2 5 5 60 621;7 52 4 12 82 9 80;7 23 123 31 45 89 90]
B =
1 21 15 41 322 52 21
4 4 2 5 5 60 621
7 52 4 12 82 9 80
7 23 123 31 45 89 90
>> TransposeArray(B)
ans =
90 89 45 31 123 23 7
80 9 82 12 4 52 7
621 60 5 5 2 4 4
21 52 322 41 15 21 1
>>