Please explain how to get the
answer of 12, I got 27 and it is incorrect
Homework Answers
AaBbC1C2 * AaBbC1C2
first let`s consider the cross
AaBb * AaBb
the number of possible phenotypes in dihybrid cross with the simple dominance relationship is 4,
number of phenotypes=2^ number of heterozygous loci= 2^2=4
for the co-dominant loci
C1C2 * C1C2
| C1 | C2 | |
| C1 | C1C1 | C1C2 |
| C2 | C1C2 | C2C2 |
here C1C1, C1C2, C2C2 have different phenotypes, number of possible phenotypes=3
so total number of different phenotypes can be produced= number
of phenotypes produced by AaBb * AaBb 
number of phenotypes produced by C1C2 * C1C2=43=12
so the answer is c) 12
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Please explain how to get the
answer of 12, I got 27 and it is incorrect...
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