Question

Help me draw this *mechanism*please! My acid catalyst is H2SO4 (sulfuric acid) please show me the pre-step, nucleophilic attack, and the two proton shift. Thanks!!

+ ЛОН acid catalyst + ОН acetic acid H2O 1-propanol propyl acetate (pear)

acetic acid + 1-propanol = propyl acetate + water

Answer 1

in the presence of When Carbonylic acids are heated with alcools conc. H2 Soys esters formed. This Reaction aga Reversible in mature t is known as Esterification. are -OH + acetate tor stay + H20 acetic 1- propanol propye acid Mechanism li- Step It Protonation of carbonye group Carbony group of carborylic acid accepts a proton to form protonated carboxylic acid op CH3 TOH CH₃ Step I Nucleophilic attack by alcohol Molecull Carbonyl carton å electrophillic f hence it will undergo medeoplllic attack by Alcohol で。 H- O -0,-CH-CH, CH₂ OH ott CH₂ G OHT OH OH OH OH CH₂=4 -CH-CH₂ CH₂ molecule of a proton. OH Boto с. O it CHg Step II loss of a water Lot CH₂ CH₂ CH₂ CH₃ : OH to This oh, group gets converted to BiH which being good leaving group will be lost oc 00M2 a Molecule

SO4 + -Н, О o-CH, снен, C сн. Фон, 6) ө CH2= -Сн, н, ң, Protonated ester ) 0 — НЕ ө сна - с CH₃-C -cн, сносно осн,сн, Сн, ester propyl acetate