Question

Consider two toy cars. Car A starts from rest and speeds up with constant acceleration for...

Consider two toy cars. Car A starts from rest and speeds up with constant acceleration for a time tA until it reaches a speed of vA and then continues to travel at this speed. At the moment car A reaches its maximum speed, car B, starting at rest from the same point that car A started from, speeds up with constant acceleration aB.
a) Make a freehand plot of the speed of each car as a function of time. Label your plot with all relevant information, including any given slope information.
c) Determine how much time, ∆t, elapses between the time car B starts moving and the time car B passes car A. To do this, you will need to solve a quadratic equation. Explain your choice of sign for the radical.
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b) Make a freehand plot of the position of each car as a func- tion of time. Label your plot with all relevant information, including any given slope information.
d) Determine the ratio vB/vA, where vB is the speed of car B at the moment it passes car A. Simplify your answer as much as possible. What is the limit of vB/vA as aB → 0? Will car B always eventually overtake car A no matter how small we make aB (as long as aB is nonzero)?

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Answer #1

a)

For A For B Vlt) - - - - - - - - - T +A

c)

let the car B catch car A after time \Deltat

Consider the motion of car A :

VAo = initial velocity of car A = 0 m/s

tA = time during which the car accelerate

\Deltat = time during which the car A moves at constant speed

Position of car A is given as

XA = VAo tA + (0.5) aA tA2 + VA\Deltat

XA = (0) tA + (0.5) aA tA2 + VA\Deltat

XA = VA\Deltat + (0.5) aA tA2                                                      eq-1

Consider the motion of car B :

VBo = initial velocity of car B = 0 m/s

\Deltat = time during which the car B accelerate

aB = acceleration of car B

Position of car B is given as

XB = VBo\Deltat + (0.5) aB\Deltat2

XB = (0) \Deltat + (0.5) aB\Deltat2

XB = (0.5) aB\Deltat2                                                      eq-2

Using eq-1 and eq-2, for the cars to catch each other

XA = XB

VA\Deltat + (0.5) aA tA2 = (0.5) aB\Deltat2

(0.5) aB\Deltat2 - VA\Deltat - + (0.5) aA tA2 = 0

\Deltat = (- (- VA) \pm sqrt((- VA)2 - 4 ((0.5) aB ) ((0.5) aA tA2)) )/aB

\Deltat = ( VA\pm sqrt( VA2 - aB aA tA2 )/aB

the sign will be positive since time can not be negative

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