Question

Design applications--using 74LS163 (1) Design and construct a mod-8 counter to count from 7 to 14 using the load input and an

0 0
Add a comment Improve this question Transcribed image text
Answer #1

74LS163 Pin diagram. 16 vec 15t Rco 13- OB 12F ENP7 o Hoo of ENT a- LOAD GND 8 Scanned with CamScannerMod-8 counter (714) supply line itsv +SV ICLR CLK ♡ = 16 = IENP AND الان Ground lineо во - о - о - о - о . во - оо - - o o - - во - o o oo - - - - боо - - - - - - о 1 Table о - o-s - - - - - - - - - - o o o oSorry as i am unable to give explanation because of less time remaining mean while i will give some guidance to understand it.

RCO pin should be unconnected it is used to connect to another 74ls163 ic to increase counts.

ENP should be high as it enables the IC.

ENT should be HIGH and it enables the RCO when all the outputs are one.

CLR should be high or else it will clear the outputs and reset to 0000

CLK is applied externally so i left it as your wish.

In truth table G1 column is for load inpput and output of OR gate.

When LOAD is low the data present in ABCD will be directly displayed on the QA QB QC QD

In truth table the initial stage is indicated then only original stages are indicated.

The connections in the design are indicated with a BIG DOT.

Sorry for not giving the clear explanation and THE GATE IN THE DESIGN SHOULD BE NOR PLEASE REPLACE IT i just figured it out. sorry sorry sorry.

thanks for the question

have a nice day.

Add a comment
Know the answer?
Add Answer to:
Design applications--using 74LS163 (1) Design and construct a mod-8 counter to count from 7 to 14...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT