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Q2 Car bumpers are designed to limit the extent of damage to the car in the case of low-velocity collisions. Consider a 1420

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Answer #1

On applying conservation of energy that is loss in kinetic energy= Gain in spring potential energy

Therefore (1/2)mv^2 = (1/2)kx^2

where x is the compression of spring in meteres.

Given v=5 Km/hr= 1.38 m/s

K=9*10^4 N/m

m=1420Kg

(1/2)*1420*(1.38)^2= (1/2)*9*10^4*x^2

we get x=0.03m=30mm

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