Question

Homework 24.1: Two rotating bars are connected by a slider block P. The configuration at the instant of interest is: a = 20°, B = 50°, and b = 10 in. The bar rotating about B moves at constant clockwise angular velocity of 5 rad/s. Find the angular velocity of the bar rotating about A and the relative velocity of the slider block P with respect to the bar on which it slides. B 11

Answer 1

We con solve this by using velocity polygons. # Draw vector from `alground) perpendreal to link AP. This vector represents VPA: le Velocity i n of 'p'w.r.t 'A' taP is on slider crank yra # Draw another rector from it to DB This vector represents VDA le Velocity of why I ro' with respect À'. # VDA and VPA are two sides ! of the triangle Draw another vector along BD res prennbing Vppile velocity of Slider with respect -0! By observation, Von and Ves are I and VPA is the resultant of Dadp by law of tosorgle from DABD - AD ABBD sin (180-30) stn 30 sinoc AD = Sin 130x_{0 = 15:32 in → singo = 6.84 in BD = since X 10 - Jino Curven Woo = sradisec Von = WBOX BD = 5% 6.84 VOA = 34.2 in liec

From Dadp tan30 = VPD 130= VOA AVD IDA 13-0€ = 30 → also Vpp = 34.2 x ton30 Vpp = 19.745 to see a velocity of p' wort BD. I cos30 = VDA O VpA → UPA = 39.49 WAP X AP = 39.49 APCAD > (9) - 3:49 15.32 same length. t9a2 = 22 Yodoc pand i are same points but on different links
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