How much work needed to stretch an extra 2 cm? l m RS CWT nel de...

Question

Question

How much work needed to stretch an extra 2 cm?
l m RS CWT nel de -to -stre tan

science physics

Answer 1

Answer #1

Energy stored in spring = 0.5*K*x²

At 5 cm energy stored = 0.5*160*0.05*.0.05 = 0.2 joule

At 3 cm = 0.5*160*0.03*0.03 = 0.072 joule

Therefore work done = 0.2 - 0.072= 0.128 joule

Answer 2

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