Homework Answers
Given
spring constant k = 1.2 N/m
streche in the spring due to rotation of mass m = 0.075 kg in circular motion , is 0.05 m
the time period is T = 2pi sqrt(m/k) = 2pi sqrt(0.075/1.2) = 1.571 s
angular frequency w = 2pi/T rad/s
W =
2pi/(T*2pi) rev/s
W =
60*2pi/(T*2pi) rpm
W = 60/ T rpm
W =
60/1.571 = 38.192 rpm = 38 rpm
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