Question

Given a current of 1.3[A]; a coil radius of 0.16[m]; and N = 130, then what is the strength of the magnetic field in milliTesta? (Use three sig. figs, or write N/A if there is not enough information.) Let's say that you are given a magnetic field B = 0.00095[Tesla]. You also have an average V/d^2 = 19629[V/m^2]; what is the value for c/m? You used a function of current and some other constants to find B. B, according to this function, was constant. Considering the equation e/m = 8B^-2 * Vd^-2, and B must be constant for a given current because the equation is made only from constant B, according to my data, was not a constant value. My Vd^-2 consistently decreased B must be constant because 1 want it to be constant since the lab manual told me it B was not constant, even though it said it was, because diameter of beam is getting

Answer 1

5) I =1.3 A, r = 0.16 m, N =130

B = Nuo*i/2a

B = 130*4*3.14*10^-7*1.3/(2*0.16)

B = 0.66 mT

6) B =0.00095 T , V/d^2 = 19629 V/m^2

mv^2/r = qvB

q/m = v/rB ..(1)

From conservation of energy

K =U

1/2 mv^2 = qV

v = (2qV/m)^0.5

From(1)

q/m = (2qV/m)^0.5 /rB

q/m = 2V/r^2B^2

e/m = 2*19629/(0.00095^2)

e/m = 0.435*10^11 C/kg

7) e/m = 8 B^-28*V*d^-2

correct option is (b)