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Steam enters a nozzle operating at steady state at 30 bar, 320 deg C with a...

Steam enters a nozzle operating at steady state at 30 bar, 320 deg C with a velocity of 100 m/sec. The exit pressure and temperature are 10 bar and 200 deg C respectively. The mass rate of flow of steam is 2 kg/sec. Neglect heat transfer and potential energy. Determine, exit velocity in m/sec and inlet and exit flow areas in m2.

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30 bar is equal to 3Mpa, 10 bar is equal to 1MpaFrom steam properties at P1 = 3MPa and T1 = 320 deg C, we get enthalpy h1 3040 kJ/kg, and specific volume v1 0.085 mA3/kg From steam properties at P2 1MPa and T2 200 deg C, we get enthalpy h2 2830 kJ/kg, and specific volume v1 0.206 mA3/kg Using steady flow energy equation, h1 + V142/2-h2 +V242 /2 3040*10A3100*2/2 -2830*10A3 V2A2/2 Solving this, Exit velocity V2- 655.74 m/s From mass conservation equation, m A1*V1/v1 A2*V2/v2 2 A1*100/0.085 A2*655.74/ 0.206 Solving this, inlet flow area A1 = 0.0017 m^2 = 17 cm^2 Exit flow area A2 6.2829*10A-4 m*2 6.2829 cm*2

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