Question

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kam review - Note OIn a reversible chemical reaction at equilibrium, the concetratior OF XCtne reactant) is o-1mol/L and tne concetrationoF Y(the Key? Prodoct) is o.3molL.at ascwhat woold be the A)O.3 B) 3-0 1.5 do.03 All of tne following may occur attre active site of an enay me except? A) bond distorsion 6 proton transfer c)e lectron transfer d) transferas es

Answer 1

Answer 1:

Equilibrium constant, Keq can be obtained by dividing the concentration of products by concentration of reactants.

product Keq = Treactant

We have,

Concentration of product = 0.3 mol/L

Concentration of reactant = 0.1 mol/L

Thus,

Keq =

Keg = 3.0

Correct choice : Keq = 3.0

Answer 2:

Active site is the site which actually takes part in a chemical reaction. Electron/proton transfer, transferases can occur at the active site. Bond distortion blocks activity of active site, and this is not a desirable feature of active site. Hence correct choice should be :

(a) Bond distortion.