Question

Write a C++ program to compute both roots of the quadratic equation when the

user provides the three coefficients A, B, and C.

Specifically,

A.

Display “Your Name”

B.

Display “Project_2 Problem_1”

C.

Display “This program computes both roots of a quadratic equation”

D.

Display “given the coefficients A, B, and C”

E.

Real_1 = 0

F.

Real_2 = 0

G.

Imag = 0

H.

D = 0

I.

DD =0

J.

Flag = ‘Y’

K.

DO

a.

A = Display “Enter A”

b.

B = Display “Enter B”

c.

C = Display “Enter C”

d.

D = (pow(B,2.0) – 4*A*C)

e.

If D < 0 Then

i.

DD = sqrt(4*A*C – B*B)

ii.

Imag = DD/(2*A)

iii.

Real_1 = -B/(2*A)

iv.

Real_2 = -B/(2*A)

f.

If D == 0 Then

i.

Imag = 0

ii.

Real_1 = -B/(2*A)

iii.

Real_2 = -B/(2*A)

g.

If D > 0 Then

i.

Imag = 0

ii.

Real_1 = (-B + sqrt(D))/(2*A)

iii.

Real_2 = (-B – pow(D,0.5))/(2*A)

h.

Display “Solution 1 is = “ << Real_1 << “ ” << “+j” << Imag)

i.

Display “Solution 2 is = “ << Real_2 << “ ” << “-j” << Imag)

j.

Display "Do you want to run the program again? (Y = yes, N =

no)");

L.

While (Flag == ‘Y’ || Flag == ‘y’)

M.

Return (0

Answer 1

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int flag;
while(1){
   float A,B,C,x1,x2, D, real, imgnry;
   cout<<"the quadratic eqn in the form of Ax^2 + Bx + C"<<endl;
   cout<<"Enter A:";
   cin>>A;
   cout<<"Enter B:";
   cin>>B;
   cout<<"Enter C:";
   cin>>C;
   D=B*B- 4*A*C; //discriminant
   if(D>= 0)
   {
   cout<<"Roots are real but different"<<endl;
       x1=(-B+sqrt(D))/(2*A);
   x2=(-B-sqrt(D))/(2*A);
   cout<<"x1 = "<<x1<<endl; //root 1
   cout<<"x2 = "<<x2<<endl;//root 2
   }
   else if (D == 0)
   {
cout << "Roots are real and same" << endl;
x1 = (-B + sqrt(D)) / (2*A);
cout << "x1 = x2 =" << x1 << endl;
}
   else
   {
   cout<<"Roots are complex"<<endl;
       real=-B/(2*A);//real part
   imgnry =sqrt(-D)/(2*A);//imaginary part
   cout<<"x1 = "<<real<<"+"<<imgnry<<"i"<<endl; //root 1
   cout<<"x2 = "<<real<<"-"<<imgnry<<"i"<<endl; //root 2
   }
   cout<<"Do you want to run program again?press(1 = yes, 2 = No):";
   cin>>flag;
   if(flag!=1)
       break;
   }
}

M 1 2 3 4 5 6 7 8 9 10 M 11 12 13 14 15 16 17 #include <iostream> #include <cmath> using namespace std; int main() { int flags while(1){ float A,B,C,x1,x2, D, real, imgnry; cout<<"the quadratic eqn in the form of Ax^2 + Bx + C"<<endl; cout<<"Enter A:"; cin>>A; cout<<"Enter B:"; cin>>B; cout<<"Enter c:"; cin>>C; D=B*B- 4*A*C; //discriminant if(D>= 0) { cout<<"Roots are real but different"<<endl; x1=(-B+sqrt())/(2*A); x2=(-B-sqrt())/(2*A); cout<<"xi = "<<x<<<endl; //root 1 cout<<"x2 = "<<x2<<endl;//root 2 else if (D == @) { cout << "Roots are real and same" << endl; (-B + sqrt(D)) / (2*A); cout << "x1 = x2 =" << x1 << endl; 18 19 20 21 22 23 24 25 26 27 28 29 3 x1 30 1 else } { 31 32 보 mmmmm 33 34 35 ليلا ليا 36 37 38 39 40 41 42 43 cout<<"Roots are complex"<<endl; real=-B/(2*A);//real part imgnry Esqrt(-D)/(2*A); // imaginary part cout<<"x1 "<<real<<"+"<<imgnry<< "i"<<endl; //root 1 cout<<"x2 = "<<real<<"-"<<imgnry<< "i"<<endl; //root 2 cout<<"Do you want to run program again?press (1 = yes, 2 = No):"; cin>>flagi if (flag!=1) break;

x1 X2 the quadratic eqn in the form of Ax^2 + Bx + C Enter A:1 Enter B:0 Enter C:36 Roots are complex -0+6i -0-6i Do you want to run program again?press(1 = yes, 2 = No):1 the quadratic eqn in the form of Ax^2 + Bx + C Enter A:1 Enter B:0 Enter C:-36 Roots are real but different x1 = 6 x2 -6 Do you want to run program again?press(1 = yes, 2 = No):2