Question

how to solve number 2 and 3

The following chemicals have the indicated formula weights: Sucrose 342.3, Potassium dihydrogen phosphate (KH P04) 136.09, Tris 121.14 You also have the following solutions already made: 20% SDS, SM NaCl, 500 mM EDTA, You have a 40% glycerol solution, and 10X TBE pt) mularul Mag List the steps to make the following buffers (be specific and show calculations): 1. 1 liter of a solution containing: 0.5 M sucrose, 0.05 M NaCl, 0.02 M KH2PO4(1 ar Mx (mW x Volume) =gre MW x Volume 0.5m x(342,3 glind x 11 =171. 18 g Su. VIXCI=V2X02'ci. V2.)C2 - 1LYUOM: 0.1 SM MAC May 2=th CTS 5M 3). OZMK_42PO4 = M xu = x11310.098/ ml. 2.500 ml of 0.25 M sucrose, 2 M NaCl, and 10 mM Tris (1 pt) Dilution at VI 1.11.18 Kb for 3. 100 ml of 10% SDS, IM NaCl (1 pt) 4. 100 ml of a 10% glycerol solution (1 pt)

Answer 1

QUESTION 2 In this case, you need to work in each reagent in order to calculate the best amount of each. 0.25 M sucrose You need to use the molarity equation as follows This is what you need to calculate M= gr Mx(MW x Volume) = gr 0.25 M x (342.3 g/mol x 0.5L) = 42.7 grams You need 42.7 grams of sucrose MW x Volume 2 M NaCl In this case, you have a stock solution of NaCl of 5 M. So, you need to use the dilution equation V1 x C1 = V2 x C2 V1= This is what you need to calculate V2= 1 L C1= 5 M C2=2 M = 0.2 L or 200 mL V2 x C2 = 0.5 L x 2M C1 = ci 5M You need 200 mL of NaCl

0.02 M KH2PO2 In this case, you need to use the molarity equation again M= gr This is what you need to calculate MX(MW x Volume) = gr 0.01Mx (136.09 g/mol x 0.5 L) = 0.68 grams or 680 milligrams You need 680 milligrams grams of KH PO, MW x Volume Once you have added each reagent into a volumetric balloon, you will add 800 mL of distilled water in order to prepare your solution of 500 ml Note: According to Chegg's guidelines, you have to send just one question. Please, send each question separate so all experts can answer each of your questions. Thank you!