Two traveling sinusoidal waves are described by the wave functions y1 = 4.80 sin [π(4.10x −...
Two traveling sinusoidal waves are described by the wave functions
y1 = 4.80 sin [π(4.10x − 1125t)]
y2 = 4.80 sin [π(4.10x − 1125t − 0.250)]
where x, y1, and y2 are in meters and t is in seconds.
(a) What is the amplitude of the resultant wave function
y1 + y2?
Homework Answers
Angle between the phasors = π * 0.250 = π/4 rad
So resultant ampllitude A = sqrt(A1^2+A2^2 + 2A1A2 cos phi )
A = sqrt(4.8^2+4.8^2 + 2*4.8*4.8 cos (π/4) )
= 8.869 m answer
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