Problem 3: Consider an 6 pole 3-phase AC induction motor being driven at 60 Hz a)...
Q4. A six-pole, three-phase, 60 Hz induction motor is operating at a speed of 1164 rev min. The input power at this speed is 33 kW and the stator copper loss is 1200 W. Find a) Slip b Airgap power c Rotor copper loss d) Developed torque e) Developed horsepower f) If the rotational losses are 500 W, find the output torque and horsepower
6. A 3-phase 2.2 kV 25 Hz squirrel cage induction motor draws a line current of 224 A and a total power of 777 kW when operating at full load. The full-load speed is 245 rpm. The stator is wye connected and has an effective resistance per phase of 0.125 Ω. The stator iron (core) loss is 8.88 kW; friction and windage losses are 4.54 kW. Calculate at full-load conditions: b. power supplied to the rotor, a. the power factor;...
A three-phase, six-pole 440 V, 60 Hz induction motor has the following per-phase equivalent circuit parameters referred to the stator: R1 = negligible, R’2 =0.3 Ω, Rφ = infinite, X1 = 1.131 Ω, X’2 = 1.131 Ω and Xφ = 37.7 Ω. Rotational losses are negligible. Assume the stator is connected to a 440 V, 60 Hz source and use the 6-parameters IEEE model. a) Determine the motor starting torque. (5 points) b) Calculate the motor breakdown torque. (5 points)...
A three-phase, 2.2 kV, 60 Hz,
Y-connected induction motor has the following parameters: R1 = 0.2
Ω R2` = 0.4 Ω X1 + X2` = 1.5 Ω The motor’s full load speed is 580
rpm. Ignore the rotational losses and calculate: a. Full load
torque b. Output power rating c. Starting current d. Starting
torque
No poles were provided
A three-phase, 2.2 kV, 60 Hz, Y-connected induction motor has the following parameters: The motor's full load speed is 580 rpm....
Consider a 50 kW, 3-phase, 380 V line-to-line, 50 Hz, 6 pole Y-connected wound-rotor induction motor. The stator winding ac resistance is 0.1 Ω/phase. The effective stator-to-rotor turns ratio is 2. The exciting branch is negligible. It is found that when an external resistor of 0.09 Ω/phase is connected to the rotor terminals maximum starting torque of 1150 Nm is obtained. a. Compute the internal mechanical power and the internal torque developed by this motor when it drives a load...
Question 11: (3 marks) A 6 pole, 60 Hz, star connected three-phase induction motor has a rating of Pm = 55 kW and line voltage = 420 V. The slip of the motor is 2% at 0.9 power factor lagging. If the full load efficiency is 95%, calculate the torque developed in the motor.
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...
A. A three-phase ac induction motor drives a mechanical load. The motor's terminal voltage is 470V, 60 Hz. The motor's line current is 175 A, and the power factor is 0.85 lagging The motor's output power is 140 hp and the motor rotates at a speed of 1735 rpm. The motor's copper and core losses total 8.5 kW combined 1. Determine the number of poles of this motor 2. Determine the motor's shaft torque (N-m). 3. Determine the motor's rotational...
Please solve this question. Thank you.
A two-pole, 75kW, 440 V, 50 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters, in Ω/phase referred to the stator: R1-0.075, XI 0.17, xm-72, R2-0.065 and X-0.17. Its rated slip is 4%. Assume that the mechanical losses are 1 kW and the core losses are 1.1 kW. Compute: a. The rated input current b. The rated power factor. c. The pullout torque d. The induced and load torques at rated conditions....
A 3-phase, 460 V, 1740 rpm, 60 Hz, 4-pole wound-rotor induction motor has the following parameters per phase: R1 = 0.25 Ω, ' 2R = 0.2Ω, ' 1 2 X = X = 0.5Ω, 30 m X = Ω. The rotational losses are 1700 W. With the rotor terminals short-circuited, find: 1. at starting: • current when started direct on full voltage, • a torque 2. at full load: • slip • current • ratio of starting current to full-load...