Question

engineering computation

4. You were just hired for a summer internship with one of the area's best software compa- nies; however, on your first day of work you learn that for the next three months, the only job you will have is to convert binary (base 2) numbers into decimal numbers (base 10). You decide to write a script that will repeti- tively ask the user for a binary number and return its decimal equivalent until an illegal number (one containing digits other than 0 or 1) is entered. The number entered should contain only the digits 0 and 1. The rightmost digit has the value 2º and the digit N places to the left of that has the value 2N. For exam- ple, entering 110101 returns 53 = 25 + 24 + 23 + 2° You must use iteration to solve this problem. Note: The input (...) function prompts the user for a value, parses the characters entered according to normal MATLAB rules, and returns the result.

Answer 1

Here is the code for your problem.

function decimal = mybin2real(binarystring)

    % Converts an input string of 1s and 0s to a number.

    Num1 = binarystring;

    LN1 = length(Num1);

    dec1 = 0;

    for ii = 1 : LN1

        dec1 = dec1 + str2double(Num1(LN1-ii+1)) * 2^(ii-1);

    end

    decimal = dec1;

end

while true

% this is the loop that runs forever

    binarystring = input("Enter a binary number: ", 's');

    if isequal((binarystring == '1') + (binarystring == '0'), ones(1, length(binarystring)))

    % display output

        decimalNumber = mybin2real(binarystring)

    else    

    % exit the loop if number include other symbols except 1 and 0

        break;

    end

end

Here is the screenshot of the code if the indentation is not clear.

function decimal = mybin2real(binarystring) % Converts an input string of 1s and Os to a number. Num1 = binarystring; LN1 = length(Num1); dec1 = 0; for ii = 1 : LN1 dec1 = deci + str2double(Num1(LN1-ii+1)) * 2^(ii-1); end decimal = dec1; end 14 15 while true % this is the loop that runs forever binarystring = input("Enter a binary number: ",'S'); if isequal((binarystring == '1') + (binarystring == '0'), ones(1, length(binarystring))) % display output decimalNumber = mybin2real(binarystring), else % exit the loop if number include other symbols except 1 and 0 break; 17 18 end 22 end

Here is the output of the code.

Hope this helps.

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