Question

（Python)Implement the function deep_list, which takes in a list, and returns a new list which contains only elements of the original list that are also lists. Use a list comprehension.

def deep_list(seq): ""

"Returns a new list containing elements of the original list that are lists.

>>> seq = [49, 8, 2, 1, 102]

>>> deep_list(seq) []

>>> seq = [[500], [30, 25, 24], 8, [0]]

>>> deep_list(seq) [[500], [30, 25, 24], [0]]

>>> seq = ["hello", [12, [25], 24], 8, [0]]

>>> deep_list(seq) [[12, [25], 24], [0]] """ "

*** YOUR CODE HERE ***"

Answer 1

def deep_list(seq):
    return [x for x in seq if type(x)==list]

# Testing
print(deep_list([49, 8, 2, 1, 102]))
print(deep_list([[500], [30, 25, 24], 8, [0]]))
print(deep_list(["hello", [12, [25], 24], 8, [0]]))

Output:

[[500], [30, 25, 24], [0]] [[12, [25], 24], [0]] Process finished with exit code 0