Question

def zigzag(text): Implement a function that takes a string and returns a new string that is a zig-zag rearrangement of it like the one in the examples below. • Parameters: text is a string (no validation needed) • Examples: zigzag('12345678') → '18273645' zigzag('123456789') → '192837465' zigzag('abcdefgh') → 'ahbgcfde' zigzag('GeorgeMason') → 'GneoosragMe'

Remember, do not call input() or print()  You must have at least one loop in each function. You cannot import any module. You cannot call any Python function except range() and len(). You cannot modify the lists nor create new ones.

Answer 1

def zigzag (text):

new_string = ''

length = len(text)

if length%2 == 0:

half_length = length/2;

else:

half_length = int(length/2)

for x in range(int(half_length)):

new_string += text[x] + text[length-x-1]

return new_string

Explaination: we find length of string and loop half of it's length. On each itteration we pick first and last elements of string and concat them.

Note: you need to indent this.