Question

(Each question reads 18pts and the magnitude g of the gravitational acceleration ng is g = 9.81m/s2) Q1) A fighter-jet pilot starts to loop a loop of radius 800m in order to take advantage of a close dog-fight, and has an opportunity to hit the enemy with the jet's machine gun of muzzle speed 1036m/s at an instant at which it is seen on the hud screen that the altitude is 6562 feets, the pitch angle is 39 degrees and 6.8G of G meter value. The pilot fires the gun and hits the enemy, however some of the bullets miss the plane. Thus, what is the magnitude of the displacement vector of motion of the bullets, which miss the plane, after fire? (Ignore air friction and resistance) A
please write clearly

Answer 1

Here, the point worth noting is that the force of 6.8 G acts on a body with reference to the frame of aircraft. But once a body comes out of aircraft, i.e bullet(here) ,the only force acting on it in downward force of gravity, G with respect to earth.

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201 Tirupati Date 11 Page: Sol): | So, bere we are asked about the magnitude of displacement of the_bullets that missed the target so, suppose_after missing the Horget they fall at_boint B Hon the ground then the displacement vector becomes si 1.50, we have to calliciale LABI 6562 ft Р Note: The 60G force acts on the bullet wst to the Frame of aircraft. But, once the bullet Deaves the gun, wirt earth the only force acts bullet is G. on the So, 4: 1036 ms es 4x = 1036 COS.390 Lly = 1036 Sid 39° - 651-97 m/s = 205 mis Now when the bollets travels from point À to point B: Disblocement along y-direction, Sy: -6562 ft = 2000_7 Land also Sy = Uy(t) + 2 ay (+)? -0 tsy:-2000 m Lq: -9.8 m/s 2 Uy651:97 mis Puting values in equanon (), we get ) -2000= (651-97)+ - 4.9642 4.972 - 651.97€ - 2000 - 0

Tirupati but Time Out atong - director Date 11 Page: to = 136 and the DEO t: 136.05 SCC Solving, equation 00y we get no force acting There is on bullet So, sx 4x (t) : 805 X 136.05 109520:25 m 2000 m Sy alow, consider A os Lorigin, Bf109520.25, -2000) then Manqnihude of displacement vector LAB = 100g920.25) ? +(2000)? 1.19x1090 + 4x100 1031 11900 +4 103.11904 - TABL 109105 m. 109.1 km