1/f=1/v -1/u, v=30/7=4.28cm, real and inverted image
v/u=30/7)/15=0.285= -hi/ho ,. Hi=-2cm
So the image is real inverted and 2cm of image height
1S om in front of a converging (convex) lens with a o) A 7 om sal...
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Objects in front of a convex mirror
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