For the sketch i picked C since it says select which one.
Let me know if my explaination make sense. thank you.
Find z such that 88.1% of the standard normal curve lies to the left of z. (Enter a number. Round your answer to two decimal places.)
z =______


From normal table z =1.18

For the sketch i picked C since it says select which one. Let me know if...
1. Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the left of z = 0 is _______ 2. Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the left of z = −0.49 is _______ 3. Sketch the area under the standard normal...
Find z such that 3.1% of the standard normal curve lies to the left of z. (Round your answer to two decimal places.) Sketch the area described. 0 Need Help? Read It
Sketch the area under the standard normal curve over the
indicated interval and find the specified area. (Round your answer
to four decimal places.)The area betweenz = 1.39and z = 2.27 is .Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)P(z ≤ −2.05)= Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)P(z ≥ −1.54)=...
Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Enter a number. Round your answer to four decimal places.) The area to the left of z = 0.44 is .
Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Enter a number. Round your answer to four decimal places.) The area to the left of z = 0.42 is
Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the left of z = −1.40 is . The area to the left of z = 0.42 is . The area to the right of z = 1.58 is . The area to the right of z = −1.16 is . The area between z = 0 and z = −1.85 is ....
Would someone be able to explain this to me step by step?
Homework: 2-2 MyStatLab: Module Two Problem Set Score: 0 of 5 pts 7.2.5-T Save 4 of 15 (7 complete) HW Score: 14 87%, 9.67 of 65 pts E Question Help Determine the area under the standard normal curve that lies to the left of (a) Z 1.65, (b) Z 0.72, (c) Z 1.16, and (d) Z 1.03. (a) The area to theeft of 21.65 is (Round to four...
Provide a second interpretation of the area Select the correct choice below and till n the answer boxes to complele your choice Type integers or decimals Do not round Use ascending order) . A. The probability that a randomly selocted human pregnancy O B. aondonly selectod humanponcy lss betwds 0 The probabulity that a randomly selected human pregnancy lasts less than or more than days is Determine the area under the standard normal curve that lies to the left of...
I'm having a little bit of trouble and not sure If I am entering
it right on my calculator.
I put 2nd--> VARS--> normalCDF
lower: -1E99
upper: z score
and pressing enter
Whenever I do this, it says I am wrong. Please help!
Using a TI-84 calculator, find the area under the standard normal curve to the left of the following z-values. Round the answers to four decimal places. Part 1 of 4 is .35171x The area to the left...
i need help now please i dont get it.
!!! Question Help o Steel rods are manufactured with a mean length of 25 centimeter (cm). Because of variability in the manufacturing process, the lengths of the rods are approximately normally distributed with a standard deviation of 0.07 cm. Complete parts (a) to (d) (a) What proportion of rods has a length less than 24.9 cm? (Round to four decimal places as needed.) (b) Any rods that are shorter than 24...