Using the Hill cipher, decrypt the ciphertext, “BOHBFBTLTTNKKC” with the key, 1-1 3 K= Li -2]...

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Using the Hill cipher, decrypt the ciphertext, “BOHBFBTLTTNKKC” with the key, 1-1 3 K= Li -2] Show all steps in the Hill meth

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Answer 1

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o using the Hill cipher, decrypt the ciphertext, BOHBFBTLTIN kKc with the key - ] show all steps in the Hill Method. Sole To

dd = 1 mod 26 5xd = 1 mod 26 11 5821=1 Mod 26 adjoint Matrise (7) To Find the (-137 Here where - Matrix Now +63) then najw= -

kl 1 di adjlkt (50g 483.7 Find its modula 26 decryption key = ( 5 Then start our decryption: First device cipher into pair o

1 C=HB = [7 ] PT = (10 1517 mod 26 15 5 JJ = ( 10x7 +15x1 mod 26 (5x7+5x1 Si mod 20 6Juodze =>{*J+L8J (11) C = FB = (s] PREC

(W] c = TI = PCs JUJ med 26 2 = ( 218 ) mod 26 ( 29 ) = (x] Cui] C = NK = ( 13 ) PT- 10 15 11 13 mod 26 15 5 JLOJ - ( 130+1

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Using the Hill cipher, decrypt the ciphertext, “BOHBFBTLTTNKKC” with the key, 1-1 3 K= Li -2]...

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