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Type of DNA/RNA mutation: Type of protein mutation: 2. TTT 5' ATG 3" TAC GAG cтa...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
Given the information coding of DNA strand: 5'-TTT-TAC-GAA-GAG-TGA-3', Write the corresponding DNA template and mRNA strand...
Given the information coding of DNA strand: 5'-TTT-TAC-GAA-GAG-TGA-3', Write the corresponding DNA template and mRNA strand DNA template: 3' ------ 5' ______________ ______________ _____________ ____________ ____________ mRNA Strand: 5'------3' _____________ _____________ ____________ ____________ ______________
Complete the table below. [6] mRNA Amino Acid Mutation Effect Wild-type 5-GAA-3 Glu N/A Wild-type Mutant...
Complete the table below. [6] mRNA Amino Acid Mutation Effect Wild-type 5-GAA-3 Glu N/A Wild-type Mutant 1 DNA 3-CTT-5 5-GAA-3 3-CAT-5 5-GTA-3 3-CTC-5 5-GAG-3 3'-ATT-5 5-TAA-3 Mutant 2 Mutant 3
PART C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand...
PART C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop. Follow example below: Example: DNA à AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC mRNA à UCU GCC AUG GAG GCC ACC CAC GAA CAG ACA UAG GAA GAG UCA UAG protein à start - glu – ala –thre – hist – asp –glu – threo - stop acid acid 5. DNA à CTA TTA CGA TAC...
9. Transcribe the top strand of this DNA into RNA. Label the 3' and 5' ends....
9. Transcribe the top strand of this DNA into RNA. Label the 3' and 5' ends. DNA: 3' TAC CCC GGG AAA TTT ACT 5' 5' ATG GGG CCC TTT AAA TGA 3' S'AnGGGG CCc nUM AAA UGA? 10. Now translate your mRNA into Protein. Label the C-term and N-term.
1. Using the following DNA segment, the RNA transcribed and the translation DNA 5’ ATG CCG...
1. Using the following DNA segment, the RNA transcribed and the translation DNA 5’ ATG CCG GGT ACA TTC GGC CCA TAC 3’ DNA 3’ TAC GGC CCA TGT AAG CCG GGT ATG 5’ RNA 5’ AUG CCG GGU ACA UUC GGC CCA UAC 3’ Protein met pro gly thr phe gly pro. tyr DRAW an example of each of the following (circle the mutation that has occurred): A silent mutation A frameshift mutation A nonsense mutation A missense mutation
Answer The following Please, Name: Date: Transcription/Translation Practice Worksheet 1. Use the following DNA strand: TAC...
Answer The following Please,
Name: Date: Transcription/Translation Practice Worksheet 1. Use the following DNA strand: TAC GTC ACG AGA TGA GTT ATC ATT A. What is the mRNA synthesized from the DNA strand? B. What is the amino acid sequence that is then translated from this mRNA strand? 2. Use the following DNA stand: TAC TTG GCC ACG GAC TAA CAT GCA A. What is the complementary DNA strand of the above DNA strand? B. Using the complementary DNA strand,...
Please develop a Java program to read in a piece of DNA sequence from a FASTA format sequence fil...
Please develop a Java program to read in a piece of DNA sequence from a FASTA format sequence file (alternatively you can use the getRandomSeq(long) method of the RandomSeq class to generate a piece of DNA sequence), and then print out all the codons in three forward reading frames. Design a method called codon() that can be used to find all the codons from three reading frames. The method will take in an argument, the reading frame (1, 2, or...
please help with #4 and #5 question 5 of 5 the cross lines indicate deletion of...
please help with #4 and #5
question 5 of 5
the cross lines indicate deletion of the nucleotides.
what type of mutation is this? what is the resulting polypeptide
sequence?
3'- GTT - TAC - CTT - -CTC--TCC -TCA -GAC - ATC -GCA
-5' (template strand)
5' - CAA - ATG - GAA - -GAG--AGG - AGT - CTG- TAG -
CGT - 3' (non-template/coding strand)
answer: It's a ___________________mutation.
Final polypeptide sequence is N' - Met - GLU
_______________ ...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC ATG TCT AGG ATC. Write out the tRNA anticodons for each of the 5 codons as well. What is the complementary DNA sequence for the above DNA (the complementary sequence would be produced in DNA replication)? Suggested Format: DNA: TAC ATG TCT AGG ATC. Complementary: mRNA based on DNA: TRNAs that would pair with mRNA (the anticodon): Amino Acid Sequence: To transcribe the sequence...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
Complete the table below. [6] mRNA Amino Acid Mutation Effect Wild-type 5-GAA-3 Glu N/A Wild-type Mutant 1 DNA 3-CTT-5 5-GAA-3 3-CAT-5 5-GTA-3 3-CTC-5 5-GAG-3 3'-ATT-5 5-TAA-3 Mutant 2 Mutant 3
9. Transcribe the top strand of this DNA into RNA. Label the 3' and 5' ends. DNA: 3' TAC CCC GGG AAA TTT ACT 5' 5' ATG GGG CCC TTT AAA TGA 3' S'AnGGGG CCc nUM AAA UGA? 10. Now translate your mRNA into Protein. Label the C-term and N-term.
Answer The following Please,
Name: Date: Transcription/Translation Practice Worksheet 1. Use the following DNA strand: TAC GTC ACG AGA TGA GTT ATC ATT A. What is the mRNA synthesized from the DNA strand? B. What is the amino acid sequence that is then translated from this mRNA strand? 2. Use the following DNA stand: TAC TTG GCC ACG GAC TAA CAT GCA A. What is the complementary DNA strand of the above DNA strand? B. Using the complementary DNA strand,...
please help with #4 and #5
question 5 of 5
the cross lines indicate deletion of the nucleotides.
what type of mutation is this? what is the resulting polypeptide
sequence?
3'- GTT - TAC - CTT - -CTC--TCC -TCA -GAC - ATC -GCA
-5' (template strand)
5' - CAA - ATG - GAA - -GAG--AGG - AGT - CTG- TAG -
CGT - 3' (non-template/coding strand)
answer: It's a ___________________mutation.
Final polypeptide sequence is N' - Met - GLU
_______________ ...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC ATG TCT AGG ATC. Write out the tRNA anticodons for each of the 5 codons as well. What is the complementary DNA sequence for the above DNA (the complementary sequence would be produced in DNA replication)? Suggested Format: DNA: TAC ATG TCT AGG ATC. Complementary: mRNA based on DNA: TRNAs that would pair with mRNA (the anticodon): Amino Acid Sequence: To transcribe the sequence...
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