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In the figure, part of a long insulated wire carrying current i = 9.89 mA is bent into a circular section of radius R = 9.80

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solution - ini = 9.29 mA R = 9.8 cm field due to wine Bi= Mo ľ (+2) zak 11.H u Curvature B- blue cês 2Ř Brer is lois 1 +18 (tsolution - ini = 9.29 mA R = 9.8 cm field due to wine Bi= Mo ľ (+2) zak 11.H u Curvature B- blue cês 2Ř Brer is lois 1 +18 (t

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