Hi, I'm having a problem with finding a unit of a slope for the given function: y=(1/2)((L^2eB)/(mv)). (y is a deflection(meters), e is the charge of an electron, L is a distance (meters), m is the mass of an electron, and v is the velocity). Here, magnetic field, B, is the only variable and everything else is a constant. If so, what should be the unit for the slope?
Usually the slope is defined as

Where 
Here x is the independent variable and y is the dependent variable. If let us say that the unit of x is some X and unit if y is some Y, then the unit of slope is the ratio between Y and X. In your case you have magnetic field as a dependent variable and deflection as a independent variable. Now the slope of this can be found by evaluating

In this the unit of numerator is meter and that of denominator is Tesla. So the unit of slope is just the ratio between these two. It is given by

This is the answer.
Hi, I'm having a problem with finding a unit of a slope for the given function:...
Hi, I'm having a problem with finding a unit of a slope for the given function: y=(VqD)/(dmv). (y is a deflection(meters), V is voltage, q is a charge of an electron, D and d is a distance (meters), m is the mass of an electron, and v is the velocity). Here, Voltage, V, is the only variable and everything else is a constant. If so, what should be the unit for the slope? Or is there just no slope at...
Hi, I'm having trouble finding Theoretical Period T.
For table 1, the mass is .068kg and pendulum length is 1.31m. For
table 2, mass is 0.668kg and 25 degrees.
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Finding the charge to mass (e/m) ratio of the electron Often in physics, we look for ways to find fundamental physical constants. From the set-up demonstrated in class, we are able to find a monumental combination of two physical constants-the charge of an electron (e) and the mass of an electron (m). Since the charge of an electron (e) is well known through other experiments, we will use the ratio of charge to mass to find the mass of an...
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