Question

R1 R2 Subnet 192.168.1.128/30 fo/1 PC-1 f0/1 fo/o 192.168.1.62/26 PC-3 fo/O 192.168.1.126/26 VPCS VPCS 192.168.1.21/26 eo e1/Given This picture,

1. What is the subnet for the devices connected to IOU 1 and 2. What is the subnet for the devices connected to IOU 2.

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Answer #1

1. What is the subnet for the devices connected to IOU 1

Devices connected to IOU 1 are

192.168.1.21/26

192.168.1.22/26

Network Interface address is: 192.168.1.62/26

Here the network prefix is 26 so,take any address from the following subnet and convert to binary form and take its first 26 bits and remaining as zero’s then that will give the subnet id of that particular subnet

(where the network prefix is given in the address)

Binary equivalent of 192 is : 11000000

Binary equivalent of 168 is : 10101000

Binary equivalent of 1 is : 00000001

Binary equivalent of 21 is : 00010101

192.168.1.21 is : 11000000.10101000.00000001.00010101

take the first 26 bit and remaining as zeros

11000000.10101000.00000001.00000000 = 192.168.1.0

subnet id is : 192.168.1.0

Note: If you do this above operation with the address 192.168.1.62 or 192.168.1.22 also you will get same result, because both are also belongs to same subnet.

2. What is the subnet for the devices connected to IOU 2

Devices connected to IOU 2 are

192.168.1.103/26

192.168.1.104/26

Network interface address is : 192.168.1.126/26

Now we can to the operation with network interface address

Here the network prefix is 26 so,convert the address into binary form and take its first 26 bits and remaining as zero’s then that will give the subnet id of that particular subnet.

Binary equivalent of 192 is : 11000000

Binary equivalent of 168 is : 10101000

Binary equivalent of 1 is : 00000001

Binary equivalent of 126 is : 01111110

192.168.1.126 is: 11000000.10101000.00000001.01111110

take the first 26 bit and remaining as zeros

11000000.10101000.00000001.01000000 = 192.168.1.64

subnet id is : 192.168.1.64

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