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1. Students in a physics lab are asked to find the length of an air column in a tube close at one end that has a fundamental

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Answer #1

For one end closed tube, resonance frequencies are given by, n2 f = 7 n = 1,3,5,... Given, fundamental frequency, fi= - = 341

A.

21 7 = 341312 . 331.4+0.6 x Tc 4 x 0.2483 -= 341.3 331.4+0.6 x TC = 338.97916 = 0.6 x TC =7.57916 TC = 12.63°C

B.

fn=nfi, v= 338.979m/s f2 = 682.6Hz, L= 338.979 4* 682.6 =0.1242m f3 = 1023.9Hz, L-_338.979 4 * 1023 0 = 0.0828m f4 = 1365.2H2

C.

For both ends open tube, fn = L = = 338.979 2f1 = 2 + 341.3 = 0.4966m

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