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the enzyme hexokinase can catalyze the following reaction:

fructose + ATP -> fructose 6 phosphate + adp

if the deltaG of hydrolysis of fructose 6 phosphate to fructose + Pi is -13.8 kj/mol and hydrolysis of atp to adp + pi is -30kj/mol, calculate Keq for the reaction above (R = 8.31 j mol-1 K-1, T = 298 k

3a. The enzyme hexokinase can catalyze the following reaction: Fructose + ATP → Fructose-6-phosphate + ADP If the ΔGo of hydrolysis of fructose-6-P to fructose + Pi is-13.8 kJ/mol and hydrolysis of ATP to ADP + Pi is-30 kJ/mol, calculate Keq for the reaction above. (R = 8.31 J mot! K-1, T= 298 K) b. Will there be more fructose or fructose-6-P at equilibrium? (What direction does the reaction proceed in?) c. Why is ATP a high energy compound, whereas fructose-6-P is not?

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Answer #1

Glycolysis is a biochemical process during which a glucose molecule splits into two moles of pyruvate. This reaction yields 2 moles of ATP and two moles of NADH. The major regulatory steps of Glycolysis are three strongly exergonic, nonequilibrium reactions conducted by the enzymes, namely hexokinase, phosphofructokinase and pyruvate kinase Hexokinase catalyzes the following reaction OH O он о OH + ATP OH ADP но OH OH OH OH OH Fructose Fructose-6-phosphate The equilibrium of above equation is as follows: Fructose+P -Fructose-6-phosphate +H2OAG-13.8 kj/mol ATP + H ,O- ADP + P Fructose +ATP -Fructose-6-phosphate ADP AG43.8kj/mol Therefore, the ΔGo of overall reaction is -43 .8ki/mol. The calculation of Ke, ls as follows: ere AG -43.8kj/mol R 8.31jmol K T 298 Keq RT -4.38x101 jmol 8.31 įmor K-1x298 K 17.7 eq 4.86x 107 Therefore, the K of the reaction catalyzed by the hexokinase is 4.86x10 3b If the Kc <1, then the system contains more reactants than products, vise-versa. In the given case, the Kc >1, so system contains more products than reactants. Therefore, at equilibrium the concentration of fructose-6-P is more compared to fructose. The AG of overall is in negative state (-43.8kj/mol). So, the reaction is spontaneous and proceed towards the products Fructose-6-phopshate is a stable compound when compared to ATP. The terminal phosphates of ATP have phosphoanhydride bonds, whereas the primary phosphate bond with ribose sugar via an ester bond. So, the terminal phosphates of ATP are always in an unstable state and readily get released from ATP to from ADP + Pi or AMP PPi, which results release of energy about -30 kj/mol

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