A 2000.00 g sample of ice at 0.0 deg. C is heated until it is liquid...

Question

Question

A 2000.00 g sample of ice at 0.0 deg. C is heated until it is liquid water at 44.0 deg. C. How much heat energy was added to the sample?

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Answer 1

Answer #1

m = 2000.0 g = 2kg

Heat energy added in melting ice

Q₁ = mass of ice * latent heat of fusion = m L_f = (2 kg) x (334b kJ) = 668 kJ

Heat energy added in raising temperature of ice from 0^oC to 44^oC

Q₂ = mc∆T = (2 kg) x (4.180 kJ) * (44-0)

Q₂ = 367.84 kJ

Total heat energy added Q = Q₁ + Q₂

Q = 668 kJ + 367.84 kJ

Q = 1035.84 kJ

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Answer 2

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