Question

A 68 gram ice cube at 0°C is heated until 62 g has become water at 100°C and 6 g has become steam at 100°C. How much energy was added to accomplish the transformation?

A 68-g ice cube at 0°C is heated until 62.0 g has become water at 100°C and 6.0 g has become steam at 100°C. How much energy was added to accomplish the transformation? 62 X Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least f minimize roundoff error. k)

Answer 1

Answer Given that m,- 689 = 0.068kg M2 - 629= 0.062kg m₂ = 69=0.006Kg we know that Latent heat E68X333.55- 22681,45 specific heat of water: 629 water rained =4.186 X100X 62 = 25953.25 Latent heat to riere water to steam - 6X2256 = 13536 J Total energy = 22681.4+ 25953.2 +13536 = 62170.6J