Question

Diego and Madeline now use what they have learned to work a problem. A rectangular loop of wire with width 0.3 cm and length 0.5 cm is oriented with the normal to the face of the loop making an angle of 23° with respect to the direction of B. The B field has a magnitude of 0.47 T. Find the magnetic flux through the loop. Wb

Answer 1

Given :-

$\Theta$ = 23 degree

dB = 0.47 T

w = 0.3 x 10^-2 m

b = 0.5 x 10^-2 m

A = w x b

A = 0.5 x 10^-2 m x 0.3 x 10^-2

A = 0.15 x 10^-4 m^2

$\Phi$ = NA*cos($\Theta$)*dB

$\Phi$ = 1 x 0.15 x 10^-4 m^2 x cos(23) x 0.47 T

$\Phi$ = 6.49 x 10^-6 Wb