Homework Answers
1.
a) For the reaction
dHo = dHo(products) - dHo(reactants)
= (2 x 90.25) - (2 x -218.99)
= 618.48 kJ/mol
Endothermic reaction, dH +ve.
dGo = dGo(products) - dGo(reactants)
= (2 x 86.57) - (2 x -189.24)
= 551.62 kJ/mol
Non-spontaneous reaction, dGo +ve
b) For the reaction
dHo = dHo(products) - dHo(reactants)
= (-393.51 + 2 x -20.7) - (89.70 + 2 x -285.83)
= 226.45 kJ/mol
Exothermic reaction, dH -ve.
dGo = dGo(products) - dGo(reactants)
= (-394.38 + 2 x -33.05) - (65.27 + 2 x -237.18)
= -51.39 kJ/mol
spontaneous reaction, dGo -ve
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