V at lowest point = sqrt ( 2×9.8×2 ) = 6.261 m/s
T at lowest point = mg + mv²/r
T = 3×9.8 + 3×6.261²/2
T = 88.2 N -------------> Answer
A 1 kg solid ball is attached to the end of a 3 m string to form a pendulum. This pendulum is released from rest from a horizontal position. At the lowest point in it's swing the ball collides with a cylinder of radius 20 cm and 2 kg mass that is at rest on a horizontal surface. (a) (20 points) What is the linear velocity of the cylinder right after the collision with the pendulum. (b) (10 points) Considering...
A 1.9-kg ball is attached to the end of a 2.6-m string to form a pendulum. This pendulum is released from rest with a string horizontal. At the lowest point in its swing when it is moving horizontally, the ball collides elastically with a 2.5-kg block initially at rest on a horizontal frictionless surface. What is the speed of the block just after the collision? Show all the important physics steps.
3.0 m 7. A 3.0-kg is attached to the end of a 3.0-m long string. It is held in the horizontal position (as shown) and released. a) What is the speed of the mass as it passes through the lowest position? b) What is the tension in the string as it passes through the lowest position?
A 1.0 kg object is attached to one end of a 1.25 m long string. The other end of the string is fixed. The object is released from rest when the string is horizontal falls to a vertical 90-degree angle. What is the speed of the object as the lowest point along the path (when the string is vertical)? What is the value of the tension in the string at the lowest point? What is the work done by the...
A 0.0410- kg ball swings on the end of a 1.310- m-long string. On one swing the tension in the string is 0.878 N at the lowest point. By the second swing the ball has lost 6.3 percent of its energy. What is the ball's speed at the lowest point on the second swing?
A1 kg ball is attached to a horizontal string of length L that is fixed at the other end. The ball is released from rest and reached a speed of 10 m/s at its lowest position. The length L in (meters) of the string is: g = 10m/s2 Answer: I
A 1.8 kg ball at the end of a 1.6 m string swings in a vertical plane. At its lowest point the ball is moving with a speed of 12 m/s. (a) What is its speed (in m/s) at the top of its path? m/s (b) What is the tension (in N) in the string when the ball is at the bottom and at the top of its path? bottom of its path _______ N top of its path _________...
A mass m = 4 kg hangs on the end of a massless rope L = 1.91 m
long. The pendulum is held horizontal and released from rest.
1)
How fast is the mass moving at the bottom of its path?
m/s
2)
What is the magnitude of the tension in the string at the bottom
of the path?
N
3)
If the maximum tension the string can take without breaking is
Tmax = 337 N, what is the maximum...
A 1.8 kg pendulum bob hangs from a 2 meter string. It is pulled
to the side, position A, so that the bob is 121 cm (h on the
sketch) above the lowest position, position C. The bob is released
and begins to swing. See below.
What is its potential energy after it has swung to position B,
34.0 cm below the starting point?
And, how fast is it moving at that point?
A 0.70 kg ball on the end of a 1.10 meter long string is swung above the head of a physics student at a constant rate (assume that the string is horizontal during this motion). If the string can experience a maximum tension of 10.0 N before snapping, what is the fastest the ball can be swung?