Question

Question 2 2 pts After conducting an assay for B-galactosidase, you find that using 0.096 ml of a 102 dilution of stock enzyme solution forms 215 nmoles of product in 1.27 minutes. Calculate the activity of the stock solution in moles/(min ml).

Answer 1

1 nano mole= 10^-3u mole

so 215 nmole=215/1000 umole=0.215 umole

the activity of the solution= moles of the products formed/(time taken $\times$ volume of the solution)

= 0.215 umoles/(1.27$\times$0.096)

= 1.76 umoles/min.mL

the stock is diluted by 10^-2 times

so the activity of the stock= activity of the solution $\times$ (1/dilution factor)

= 1.76 umoles/min.mL $\times$ (1/10^-2)

= 1.76 umoles/min.mL$\times$10^2

= 176 umoles/min.mL