HomeworkLib
Question

Thank you in advance. A titration of 50 ml of 0.20 M methyl amine, CH3NH2, required...

Thank you in advance.

A titration of 50 ml of 0.20 M methyl amine, CH3NH2, required 50 ml of 0.20 M HCL to reach the equivalence point. what is the pH at this endpoint? Kb for CH3NH2 = 4 x 10^-4

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)

All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Thank you in advance. A titration of 50 ml of 0.20 M methyl amine, CH3NH2, required...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Similar Homework Help Questions

  • Consider the titration of 25.00 mL of 0.200 M methyl amine (CH3NH2). The titrant is 0.120...

    Consider the titration of 25.00 mL of 0.200 M methyl amine (CH3NH2). The titrant is 0.120 M HCl. Calculate each of the following: a. the volume of added acid required to reach the equivalence point. b. the pH at ½ the HCl needed to reach the equivalence point c. the pH at the equivalence point.

  • Part A) Consider the titration of a 28.9 mL sample of 0.21 M CH3NH2 , methylamine,...

    Part A) Consider the titration of a 28.9 mL sample of 0.21 M CH3NH2 , methylamine, with 0.114 M HBr. The Kb of methylamine is 4.4x10−4. Determine the pH at 4.4 mL of added acid. Part B) Consider the titration of a 95.3 mL sample of 0.199 M CH3NH2 , methylamine, with 0.155 M HBr. The Kb of methylamine is 4.4x10−4. Determine the volume (mL) of added acid required to reach the equivalence point. Part C) Consider the titration of...

  • 11. Consider the titration of 25.00 mL of 0.200 M methyl amine (CH3NH2). The titrant is...

    11. Consider the titration of 25.00 mL of 0.200 M methyl amine (CH3NH2). The titrant is 0.120 M HCI. Calculate each of the following: a. the initial pH of the base. b. the pH at 5.00 mL added acid c. the pH at the HCI needed to reach the equivalence point d. the volume of added acid required to reach the equivalence point. e. the pH at the equivalence point. Questions Use correct units throughout all calculations, including those involving...

  • Questions 1: Consider the titration of a 24.0-mL sample of 0.175 M CH3NH2 with 0.155 M...

    Questions 1: Consider the titration of a 24.0-mL sample of 0.175 M CH3NH2 with 0.155 M HBr. (The value of Kb for CH3NH2 is 4.4×10−4 A) Determine the initial pH B) Determine the volume of added acid required to reach the equivalence point C) Determine the pH at 4.0 mL of added acid D) Determine the pH at one-half of the equivalence point. E) Determine the pH at the equivalence point. F) Determine the pH after adding 5.0 mL of...

  • You have 25.00 mL of a 0.100 M aqueous solution of the weak base CH3NH2 (Kb...

    You have 25.00 mL of a 0.100 M aqueous solution of the weak base CH3NH2 (Kb = 5.00 x 10-4). This solution will be titrated with 0.100 M HCl. (a) How many mL of acid must be added to reach the equivalence point? (b) What is the pH of the solution before any acid is added? (c) What is the pH of the solution after 5.00 mL of acid has been added? (d) What is the pH of the solution...

  • A titration of 60.0mL of 0.30M pyridine, C5H5N, required 90.0mL of 0.20 M HCl to reach...

    A titration of 60.0mL of 0.30M pyridine, C5H5N, required 90.0mL of 0.20 M HCl to reach the equivalence point. What is the pH at this equivalence point? Kb(C5H5N) = 2.0x10^-9

  • Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. For each...

    Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. For each volume of HCl added, decide which of the components is a major species after the HCl has reacted completely. Kb for CH3NH2 = 4.4 x 10-4. 0.00 mL HCl added        50.00 mL HCl added       200.00 ml HCl added       300.00 mL HCl added      yes no  H+ yes no  H2O yes no  Cl- yes no  CH3NH2 yes no  CH3NH3+ Tries 0/45 yes no  H+ yes no  H2O yes no  Cl- yes no  CH3NH2 yes no  CH3NH3+...

  • Consider the titration of 100.0 ml of 0.200 M CH3NH2 by 0.100 M HCl. (Kb for...

    Consider the titration of 100.0 ml of 0.200 M CH3NH2 by 0.100 M HCl. (Kb for CH3NH2 = 4.4 x 10^-4) At what volume of HCl added, does the pH = 10.64?

  • What is the pH when 50.0 mL of a 0.53M solution of Methyl amine (CH3NH) is...

    What is the pH when 50.0 mL of a 0.53M solution of Methyl amine (CH3NH) is titrated with 20.70 mL of a 0.37 M solution of Perchloric Acid? This is not enough acid to reach the equivalence point. (Kb for methylamine = 4.4 X 10)

  • Consider the titration of a 30.00 mL sample of 0.175 M CH3NH2 with 0.150 M HBr....

    Consider the titration of a 30.00 mL sample of 0.175 M CH3NH2 with 0.150 M HBr. The volume of equivalence for the titration is 35.00 mL of HBr added. Kb = 4.4 x 10-4 (for CH3NH2 ) Determine: (remember to use two decimal places for pH values) (a) the pH of the sample (b) the pH at one-half of the equivalence volume (c) the pH at the equivalence volume (d) the pH when 40.00 mL of HBr has been added

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT