At 25° C and at a constant pH of 5, the inversion of sucrose proceeds with...
At 25° C and at a constant pH of 5, the inversion of sucrose proceeds with a constant half-life of 500 min. At this same temperature, but at a pH of 4, the half-life is constant at 50 min. The rate law is . What are the values of a and b?
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Answer: rate = k [sugar]-1[H+]2---------------> Yes you read is correct, not possible, but question test our knowledge.
The given rate law is
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At 25° C and at a constant pH of 5, the inversion of sucrose
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