wavelength = λ = c/f = 3x10⁸ / 64.5x10⁶ = 4.65m
AB is exactly 2λ so a standing wave, length 2λ, is set-up between A
and B,
Consider what happens at each end, The waves will meet out of
phase, so there will be a node at each end. Node to antinode
distance = λ/4. The pattern of nodes (A) and antinodes (N) will
be
N-A-N-A-N-A-N-A-N
Antinodes are where the 2 beams are in phase.
So from end A we must move a distance λ/4 to get to the nearest
point where the two beams are in phase (the first antinode). So the
answer is 4.65/4 = 1.1625m.
One radio transmitters operating at 64.5 MHz is 9.3 m from another similar transmitter B that...
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