Question

Question 1. a) Choose random value for each R1,R2,R3,R4 and R5 ranging from 5 to 150. b) Use any method determine io and Vo in the circuit as in Figure 1. c) If 10V voltage source is replaced with 30V voltage source, what is the new values of i, and Vo in the the same circuit with the same value of resistance? (use linearity) R1 R3 R2 i. + 10V R4 V R5

Answer 1

RI R3 mm R2 Cum B tii I Vo -R5 Assume R = 5kn R2 z lokn Riz 15kn Ry E lokn R5 = 5kn Ri, R2 R3 in delta in delta connection convert do' stan Connection' R1 B OR Ra Rb min ma R2 ww w R3 Rc С

RR 5X15 k=2.5k Ra z 5+15+10 Ri+R2TR3 RiR2 k = 1.66k Rb 5X10 5+15+10 R1+R₂TR3 R2 R3 Rc = 10x15 K = 5K 5+15.710 Rp + R₂ R3 Crauit redrawn as R A Rb. Ra un ti + lov Rc wwww R5 vo Ry

2.5k IT Ra mm 1-66F Rb yiot + 10V 5K R5 no Retry 15k Rb in series with R5 Req= Rb + R5 1.66k + 5k z 6.66k Rea & (Retry) are in parallel 6.66k 15K 6.66 X 15 Rul che 15 +6.66/ 4.61 kr By. KVL 10 Ra IT & I, (R1) 10 10 & IT Rat Ril 2.5k + 4.61k 1.406 MA (Retry) Retry +R btr5 (By current division rule) 1.406x107x (15 x103) (15+ 1.66 + 5) x102 0.973. mA

V 1ox.5k 0-913x10?x5X10? 4.865 V © When Vi = 10V v; 10,= 0,973MA & Vo = 4.865 When V2 = 301. = 3 X Vi source (Combination of resis tour), the given circuit is linear Voltage By linearity, we can & write, 3xion = 3 x 0.973mA lov 2.9.19 m A Vo2 = 3 x Vol = 3 X 4.865 14. 595