Question

Consider the frame and loading shown in the adjoining figure. Use the dimensions and load values in the table below. Analyse the frame and determine the reactions and internal actions required in the table below. Enter your answers in the space provided. tab- 000000000000000000000UI C Dimensions: 3.3 m 2.5 m 4 m 22m c Loading: w 20 kN/m ] Results: Provide Answer for the followings to an accuracy of 2.5% Absolute Value Unit Direction Reactions Dy Member Forces Shear force in member CE Vce= Mc= Maximum moment in member BC Mmax= Location of maximal moment Mmax=1 From point C

Answer 1

Soph, Beam FBD: W = 20 kN/m A 2.5mi B 4m 3.966 m 3. 3m HDD HD TARD a 2-2 ook HE calculation of Reactions- Efx=0 - Ho-HE= 0 since By Hinge so EMB=0 Ho (3-3)=0 Hool HE=0 {fy=0 ) RotRE = 20 (4+2-5) = 130 KN EMp = 0 = (20X25X1-25) + RE ( 4+2-2) - (20X 4x2) = 0 TRE = 15.726 KN I Ro=114.274 KN Shear force in member CE : coso = 0.5547 VCE = -RE. cos o = - (15.726)(0-5547) VCE = -8.723 KN sign convention V prve 1 l tve

Moment at 'C' : Me= Rp(2.2) = 15-726 (2.2) (tve) Mc = 34.597 KN-m maym moment in member B c' 64.2747 maximum moment in member BC Mmax = 62-5 KN-m KN (+) - 0-786m SFD 3:214m- (-) 1 15.726 kN (Hogging) 40.78 KN-ma 34.597 KN-u BND C Location of = 4m Mimar from point 'c' 0.786 m 162-5KNM unit value 114.274 KN Direction Upward (1) Upward (1) Reactions Dy = Ro Ey = RE Member forces 15.726 KN KN 8.723 NCE upward (Right side of plane), X-X 34.597 Me KN-m 62.5 KN-m Sagging ( +ve > clockwise) Hogging (-ve s anticlockwise) from point 'C' in BC Mmax location of Mmax| 4.0 m

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